About this calculator
With Kf and Kb (1.86 and 0.512 for water) it also gives the change in freezing and boiling points, as in Class 12 Solutions.
How to use it
- Enter the solute formula or molar mass.
- Enter the masses of solute and solvent.
- Read the molality and point changes.
The formula
m = moles of solute ÷ kg of solvent; ΔTf = Kf × m; ΔTb = Kb × m
- Kf, Kb
- cryoscopic and ebullioscopic constants
Worked example
18 g of glucose in 500 g of water
- Moles = 18 ÷ 180.16 = 0.0999.
- m = 0.0999 ÷ 0.5 = 0.200 m; freezing point falls by 0.372 K.
What the result means
For ionic solutes multiply ΔT by the van ’t Hoff factor i, about 2 for NaCl.
Assumptions
- Dilute, ideal solutions; non-volatile solute.
Limitations
- Concentrated solutions deviate from these simple formulas.
Frequently asked questions
Why use molality instead of molarity?
It does not depend on temperature.
What is Kf for water?
1.86 K kg/mol.
Do I use solvent or solution mass?
Solvent only.
Last reviewed on 6 October 2026. Found a mistake? Tell us.

