Binomial Probability Calculator

The binomial distribution counts successes in a fixed number of independent trials that each succeed with the same probability, such as heads in 10 coin tosses or defective items in a batch.

Between 0 and 1.
Results update as you type.

P(X = 6)

0.205078

20.508%

P(X ≤ 6)
0.828125
P(X < 6)
0.623047
P(X ≥ 6)
0.376953
P(X > 6)
0.171875
Mean and standard deviation
5 and 1.5811388np and √(np(1 − p))
Distribution
Distribution
kP(X = k)P(X ≤ k)
00.0009765630.000976563
10.009765630.0107422
20.04394530.0546875
30.1171880.171875
40.2050780.376953
50.2460940.623047
60.2050780.828125
70.1171880.945313
80.04394530.989258
90.009765630.999023
100.0009765631

About this calculator

You get the exact probability and every cumulative version at once.

How to use it

  1. Enter n, p and k.
  2. Read the probabilities.

The formula

P(X = k) = nCk × pᵏ × (1 − p)ⁿ⁻ᵏ
n
number of trials
k
number of successes
p
probability of success in one trial

Worked example

Exactly 6 heads in 10 tosses

  1. 10C6 × 0.5⁶ × 0.5⁴ = 210 ÷ 1,024 = 0.2051.
  2. P(X ≤ 6) = 0.8281.

What the result means

The mean is np and the standard deviation √(np(1 − p)).

Assumptions

  • Trials are independent with the same p.

Limitations

  • Sampling without replacement from a small group needs the hypergeometric distribution instead.

Frequently asked questions

What are the conditions for a binomial distribution?

A fixed number of trials, two outcomes each, the same probability each time, and independent trials.

What is the difference between P(X ≤ k) and P(X < k)?

P(X ≤ k) includes k itself; P(X < k) stops at k − 1.

When can I use the normal approximation?

When np and n(1 − p) are both at least about 10.

Last reviewed on 6 October 2026. Found a mistake? Tell us.